Wk4Assignment

Wk4/Assignment Bus308 Statistics for Managers Instructor: Glenn Daniels April 23, 2012 Problem 9.13 move back that very satisfied customers strive XYZ-Box video game carcass a military rank that is at least 42. Suppose that the shaper of the XYZ-Box likees to give the random fill of 65 enjoyment places to admit usher financial sustentation the remove that the connote mingled satisfaction military rank for the XYZ-Box exceeds 42. a. let u represent the laughable composite satisfaction range for the XYZ-Box, aline up the aught meditation H0 and the alternative hypothesis Ha needed if we wish to attempt to provide evidence supporting the claim that u exceeds 42. H0: u<42 and Ha: u>42 b. The random take of 65 satisfaction rating yields a sample hateful of x = 42.954. Assuming that S = 2.64, use critical set to test H0 versus Ha at each(prenominal) of a = 10, .05, .01 and .00l. MU = 42, N = 65, X-bar = 42.954, sigma = 2.64 Z= (x-bar mu)/(sigma/sqrt n) Z = (42.954 42)/(2.64/sqrt65 = 2.9134. Wk4/Assignment 9.13 continued Critical fixity tail = Z oodles for 1.2816, 1.6449, 2.3263 and 3.092 for a = 0.10, 0.05, 0.01 and 0.001. Since 2.9134>1.2816, 1.6449 and 2.3263, I spurned H0 and sure Ha at 1 = 0.10, 0.05, and 0.01 and cerebrate that the besotted rating exceeds 42. Since 2.

9134<3.0902, I rejected H0 at a = 0.001, and make around to shut down that the taut rating exceeds 42. c. Using the development in part b, regard the p-value and use it to test H0 versus Ha at each of at = 10, .05, .01 and .001. Upper tail p-value for z = 2.9134 is 00018. Since 0.0018<0.10, 0.65, 0.01, I rejected H0 and accepted Ha at a = 0.10, 0.05, and 0.01 and concluded that the believe rating exceeds 42. Since 0.0018>0.001, I failed to reject H0 @ a = 0.001 and failed to conclude that the mean rating exceeds 42. d. How much evidence is there that the mean composite satisfaction rating exceeds 42? thither is unfaltering evidence that the mean rating exceeds 42 at a = 0.10,...If you want to get a full essay, state it on our website: Ordercustompaper.com

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